Lets Call 50

I saw this puzzle on the site http://www.crackpuzzles.com/

Suppose two players are playing a game where we call integers. The first person who calls 50 wins. The rules are that the first person calls a number between 1 and 10. After that any new number that is called must exceed the last number by at least one and no more than by 10. For example: If the last number called is 15, then the next number that is called must be between 16-25.
I give you the first mover advantage, devise a strategy to win.

Update (11/12/09): Solution in comments!!

Comments

  1. Ankit5:26 PM, November 10, 2009

    Irrespective of what other player call, if i start first, I wud call following number

    6, 17, 28, 39, 50
    :)

    ReplyDelete
  2. Pratik Poddar5:27 PM, November 10, 2009

    yo daane!!
    correct solution :)

    ReplyDelete
  3. Tiger7:35 PM, November 11, 2009

    yup this was an easy one...

    ReplyDelete
  4. Aytidaa Madras4:11 PM, December 10, 2009

    easy_max:P

    ReplyDelete
  5. Pratik Poddar1:02 PM, September 08, 2026

    Agreed - once you see that you want to call 6, 17, 28, 39, 50 (everything congruent to 6 mod 11), it solves itself. (replied using AI)

    ReplyDelete
  6. Pratik Poddar1:03 PM, September 08, 2026

    :P - the trick is all in calling 6 first and then always making the two calls in a round add to 11. (replied using AI)

    ReplyDelete

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