Losing at Dice

When six dice are rolled, the number of different numbers which can appear range from 1 to 6. Suppose that once every minute, the croupier rolls six dice and you bet $1, at even odds, that the number of different numbers which appear will be exactly 4.

If you start with $10, roughly how long will it be, on average before you are wiped out?

:)

Update (11/12/09): Solution in comments!!

Comments

  1. harsh agrawal9:40 PM, October 09, 2009

    12 minutes.....

    ReplyDelete
  2. violator12:07 AM, October 10, 2009

    about 22 minutes

    ReplyDelete
  3. vio12:08 AM, October 10, 2009

    about 22 minutes

    ReplyDelete
  4. Pratik Poddar12:15 AM, October 10, 2009

    sorry guys...
    :(

    Not the correct answer :(

    ReplyDelete
  5. Unknown1:15 PM, October 10, 2009

    eternity :P

    ReplyDelete
  6. Pratik Poddar1:57 PM, October 10, 2009

    sahi hai jaadu...
    :)

    badhiyaan :)

    @junta... probability that the even occurs is > 0.5, and so, he would expect his money to grow :)

    ReplyDelete
  7. Novocaine10:11 PM, October 10, 2009

    I am not able to figure out how many cases would it take to arrange - 123412 and 123411 types of cases (this no*360) should be the total possible cases

    ReplyDelete
  8. Novocaine12:22 AM, October 12, 2009

    Hmm, Got it - 6C4(4C1 * 6!/3! + 4C2 * 6!/(2!*2!))/6^6

    Hmm good one.

    ReplyDelete
  9. Pratik Poddar10:09 AM, October 12, 2009

    :)

    @ranka... jee times... huh!! :)

    ReplyDelete

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